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JEE Main Test 131
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JEE Main Test 131
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  • Question 1/10
    4 / -1

    A plane electromagnetic wave of frequency 20 MHz travels through a space along x-direction. If the electric field vector at a certain point in space is 6 Vm-1, what is the magnetic field vector at that point?

    Solutions

     

  • Question 2/10
    4 / -1

    The equation of tangents drawn from the origin to the circle x2 + y2 - 2rx - 2hy + h2 = 0 are

    Solutions

     

  • Question 3/10
    4 / -1

    According to Newton's corpuscular theory, the speed of light is

    Solutions

    The Newton’s theory of refraction concludes that velocity of light in air medium is less than velocity of light in denser medium.

     

  • Question 4/10
    4 / -1

    A parabola has the origin as its focus and the line x = 2 as the directrix. Then, the vertex of the parabola is at

    Solutions

    We know vertex is a mid – point of focus and directrix

    i.e. (1, 0) is the vertex

     

  • Question 5/10
    4 / -1

    Carbon cannot reduce Fe2 O3 to Fe at a temperature below 983 K because

    Solutions

    Below 983K, standard change in free energy for the formation of Fe2O3 is more than that of formation of CO2 from CO. Therefore CO is better reducing agent for Fe2O3 below 983K.

          Fe2O3 + 3CO → 2Fe + 3CO2

    Above 983K, standard change in free energy value for the formation of Fe2O3 is more than that of CO formation from carbon (coke). At this temperature carbon has a higher affinity towards oxygen than iron. Hence above 983K, carbon (coke) is better reducing agent for Fe2O3.

          Fe2O3 + 3C → 2Fe + 3CO

     

  • Question 6/10
    4 / -1

    If 2y = x and 3y + 4x = 0 are the equations of a pair of conjugate diameters of an ellipse, then the eccentricity of the ellipse is

    Solutions

     

  • Question 7/10
    4 / -1

    Which of the following is the strongest base?

    Solutions

    In piperidine nitrogen atom is SP3 hybridized which has a less S – character while in pyridine Nitrogen atom is SP2 hybridized which has more S – character. Therefore held by the nitrogen nucleus in pyridine which has more S – character. In piperidine ione pair of electrons are less tightly held and are easily available for protonation therefore piperidine is a stronger base than pyridine.

     

  • Question 8/10
    4 / -1

    With respect to graphite and diamond, which of the statement(s) given is (are) correct?

    Solutions

     

  • Question 9/10
    4 / -1

    IUPAC name of (CH3)3 CCl is

    Solutions

     

  • Question 10/10
    4 / -1

    The IUPAC name for tertiary butyl iodide is

    Solutions

     

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