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JEE Main Test 137
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JEE Main Test 137
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  • Question 1/10
    4 / -1

    Three identical bodies of mass M are located at the vertices of an equilateral triangle of side L . They revolve under the effect of mutual gravitational force in a circular orbit, circumscribing the triangle while preserving the equilateral triangle. Their orbital velocity is

    Solutions

     

  • Question 2/10
    4 / -1

    A block of mass 2 kg is at rest on a floor. The coefficient of static friction between block and the floor is 0.54. A horizontal force of 2.8 N is applied to the block. What should be the frictional force between the block and the floor? (take, g =10 m/S2)

    Solutions

     

  • Question 3/10
    4 / -1

    Solutions

     

  • Question 4/10
    4 / -1

    A block of mass 0.50 kg is moving with a speed of 2 ms -1 on a smooth surface. It strikes another mass of 1kg and then they move together as a single body. The energy loss during the collision is

    Solutions

     

  • Question 5/10
    4 / -1

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  • Question 6/10
    4 / -1

    A wire of length L and radius r fixed at one end and a force F applied to the other end produces an extension l . The extension produced in another wire of the same material of length 2L and radius 2r by a force 2F, is

    Solutions

    Extension produce as that  in the other wire.

     

  • Question 7/10
    4 / -1

    The surface area of a black body is 5 × 10-4 m2 and its temperature is 727°C. The energy radiated by it per min is (σ = 5.67 × 10-8 Jm-2 – s-1 – K-4)

    Solutions

     

  • Question 8/10
    4 / -1

    Eight equal drops of water are falling through air with a steady velocity of 10 cms -1. If the drops combine to form a single drop big in size, then the terminal velocity of this big drop is

    Solutions

     

  • Question 9/10
    4 / -1

    A black body is heated from 27°C to 927°C. The ratio of radiation emitted will be

    Solutions

     

  • Question 10/10
    4 / -1

    The coefficient of pn qn in the expansion of [(1 + p) (1 + q) (p + q)] n is

    Solutions

    Using principle of mathematical induction,

    We have (1 + p)  (1+q) (p+q)  ,  for n=1

    i.e,  = (1+p+q+pq) (p+q)

     

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