Please wait...

JEE Main Test 140
Menu grid icon
Result Result point icon
JEE Main Test 140
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    4 / -1

    The circles x2 + y2 + 6x + 6y = 0 and x2 + y2 - 12x - 12y = 0

    Solutions

     

  • Question 2/10
    4 / -1

    Solutions

     

  • Question 3/10
    4 / -1

    Solutions

     

  • Question 4/10
    4 / -1

    Solutions

     

  • Question 5/10
    4 / -1

    The entropy of a perfectly crystalline material is zero at 0°C. This is statement of

    Solutions

    Entropy is a measure of degree of disorder or randomness of the molecules of the system. It increases when temperature of the system increases.

    According to third law of thermodynamics – entropy of all pure crystalline substance is taken as zero at absolute zero temperature.

     

  • Question 6/10
    4 / -1

    B(OH)3 + NaOH ⇌ NaBO2 + Na [B(OH)4] + H2O. How can this reaction is made to proceed in forward direction ?

    Solutions

    B(OH)3 + NaOH ⇌ NaBO2 + Na[B(OH)4] + H2O.

    The given reaction is a reversible reaction. If some quantity of C is -1, 2-diol is added to the reaction mixture, reaction moves in forward direction.

     

  • Question 7/10
    4 / -1

    Name of following compound according to IUPAC nomenclature is

    Solutions

    Aldehyde has more priority than nitro and alkoxy groups. So, IUPAC name is 4 – methoxy – 2 – Nitrobenzaldehyde.

     

  • Question 8/10
    4 / -1

    Which of the following mentioned is a type of hydrocarbon?

    Solutions

    A copound of carbon and hydrogen only is known as hydrocarbon. There are three types of hydrocarbon – saturated, unsaturated an anomatic 

     

  • Question 9/10
    4 / -1

    Which kind of defect is shown by the given crystal?

    Solutions

    A schottky defect is a type of point defect in a crystal lattice. In non – ionic crystals it means a lattice vacancy defect.

    In ionic crystals, the defect forms when oppositely charged ions leave their sites, creating vacancies. There vacancies are formed in stoichiometric units, to maintains an overall neutral change in the ionic solid. The vacancies are then free to move about their own entities. Normally these defects will lead to a decrease in the density of the crystal.

     

  • Question 10/10
    4 / -1

    Naphthalene can be easily purified by

    Solutions

    Napthalene is purified by one process of sublimotion because nepthalene sublimes on heating substances which sublimes on heating are usually purified by the process of sublimation.

     

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now