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Electrochemistry Test - 5
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Electrochemistry Test - 5
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  • Question 1/10
    1 / -0.25

    The passage of current through a solution of certain electrolye results in the evolution of H2  at cathode and Cl2  at anode. The electrolytic solution is -

    Solutions

    In this Cl–  will oxidise to give Cl2 ,Na+ reduction potential has lower potential than water reduction polenlid so water will reduce to give H2 .

  • Question 2/10
    1 / -0.25

    In an electrolytic cell current flows from -

    Solutions

    In an electrolytic cell, current flows from cathode to anode in outer circuit and in daniell cell, it is the reverse direction of flow of current from anode to cathode in outer circuit.

  • Question 3/10
    1 / -0.25

    When an aqueous solution of H2 SO4  is electrolysed, the ion discharged at anode is-

    Solutions

    Electrolysis of H2 SO4
    Cathode:-
    2H+  + 2e-  - H2     (Reduction)

    Anode:-
    4OH-  - 2H2 O  + O2  + 4e-  (Oxidation)

    OH-  ions discharged at anode.

  • Question 4/10
    1 / -0.25

    1 mole of Al is deposited by X coulomb of electricity passing through aluminium nitrate solution. The number of moles of silver deposited by X coulomb of electricity from silver nitrate solution is-

    Solutions

    Since to deposit 1 mole of aluminium 3 columb of electricity is required, as the alency of silver is + 1 so 3 mole of silver will be deposited by 3C of electricity

  • Question 5/10
    1 / -0.25

    A solution of Na2 SO4  in water is electrolysed using Pt electrodes.The products at the cathode and anode are respectively -

    Solutions

    At cathode
    4H2 O + 4e– →4H2 + 4OH–
    At anode
    2H2 O →4H+ + O2 + 4e–
    Thus at cathode we will get H2 whereas at anode we will get O2 .

  • Question 6/10
    1 / -0.25

    In electrolysis of a fused salt, the weight deposited on an electrode will not depend on-

    Solutions

    In electrolysis of a fused salt, the weight deposited on electrode will not depend or temperature.

  • Question 7/10
    1 / -0.25

    The electrolysis of a solution resulted in the formation of H2  at the cathode and Cl2 at the anode. The liquid is-

    Solutions

    In this Cl– will oxidise to give Cl2 Na+ water reduction potential has higher potential than that of water reduction potential, so water will reduce to give H2 .

  • Question 8/10
    1 / -0.25

    Which loses charge at cathode-

    Solutions

    Cation loses charge at cathode as it gave electron

  • Question 9/10
    1 / -0.25

    In the electrolysis of CuSO4 , the reaction :

    Cu2+  + 2e ¯→ Cu, takes place at :

    Solutions

    As reduction will take place at cathode so reaction Cu2+ + 2e →Cu
    Will take place at cathode

  • Question 10/10
    1 / -0.25

    If mercury is used as cathode in the electrolysis of aqueous NaCl solution, the ions discharged at cathode are-

    Solutions

    If mercury  is used as cathode in the electrolysis of aqueos NaCl solution then the metal is discharged at mercury to from amalgam.

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