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Electrochemistry Test - 7
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Electrochemistry Test - 7
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  • Question 1/10
    1 / -0.25

     

    The specific conductance of a solution is 0.3568 ohm-1 . When placed in a cell the conductance is 0.0268 ohm-1 . The cell constant is-

     

    Solutions

     

     

    K = 0.3568 W cm–1
    condutance = 0.0268  Ω–1
    K = G ×1/A
    0.3568 = 0.0268 ×1/9
    13.31 cm–1

     

     

  • Question 2/10
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    A conductance cell was filled with a 0.02 M KCl solution which has a specific conductance of 2.768 ×10 - 3 ohm - 1  cm - 1 . If its resistance is 82.4 ohm at 25 ºC, the cell constant is-

     

    Solutions

     

     

    K = G. L/A
    10–3 ×2.768 = 1/R ×L/A
    L/A = 228.08 ×10–3
    = 0.2281 cm –1

     

     

  • Question 3/10
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    The variation of equivalent conductance vs decrease in concentration of a strong electrolyte is correctly given in the plot -

     

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    On decreasing the value of M will increase but increase will be hyberbolic.

     

     

  • Question 4/10
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    Which of the following solutions has the highest equivalent conductance ?

     

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    Higher the dilution higher will be the equivalent conductance

     

     

  • Question 5/10
    1 / -0.25

     

    The resistance of 0.01N solution of an electrolyte AB at 328K is 100 ohm. The specific conductance of solution is (cell constant = 1cm-1 ) -

     

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  • Question 6/10
    1 / -0.25

     

    For an electrolytic solution of 0.05 mol L-1 , the conductivity has been found to be 0.0110 Scm-1 .The molar conductivity is-

     

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  • Question 7/10
    1 / -0.25

     

    Two electrodes are fitted in conductance cell 1.5 cm apart while the area of cross section of each electrode is 0.75 cm2 . The cell constant is-

     

    Solutions

     

     

    L/A is cell constant.

     

     

  • Question 8/10
    1 / -0.25

     

    The best conductor of electricity is in 1M solution of-

     

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    That electrolyte will be the best electrolyte which has maximum number of ions.

     

     

  • Question 9/10
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    A certain current liberates 0.504 g of H2  in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time in CuSO4  solution -

     

    Solutions

     

     

    gm eq.  of H2 = gm eq. of Cu

     

     

  • Question 10/10
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    A currnet of 2.6 ampere is passed through CuSO4  solution for 6 minutes 20 seconds. The amount of Cu deposited is (At. wt. of Cu = 63.5, Faraday = 96500 C)-

     

    Solutions

     

     


     

     

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