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Alcohols Test - 8
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Alcohols Test - 8
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  • Question 1/9
    1 / -0.25

     

    Consider the following reaction sequence,

    R  —OH    R —I   R —NO2  Blue

    Hence, R —OH could be

     

    Solutions

     

     

    Both primary and secondary alcohols form blue solution in Victor Meyer test due to the formation of respectively nitrolic acid and pseudonitrol. Tertiary alcohols form neither, hence no blue colouration is observed.

     

     

  • Question 2/9
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    Consider the following reaction,

    The correct statement(s) concerning X and Y is/are

     

    Solutions

     

     


    X neither oxidised by chromic acid nor gives iodoform.

     

     

  • Question 3/9
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    Comprehension Type

    Direction : This section contains a passage describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer out of the given 4 options (a), (b), (c) and (d).

    Passage

    An organic compound X (C9 H12 O) gives the following reactions :
    i. Na - Slow gas bubble formation
    ii. Acetic anhydride - Pleasent smelling liquid
    iii. CrO3 -H2 SO4 - Blue-green solution
    iv. Hot KMnO4 - Benzoic acid
    v. Br2 -CCI4 - No decolouration
    vi. I2 + NaOH - Yellow solid is formed
    vii. X rotates the plane polarised light

    Q. 

    The structure of X is

     

    Solutions

     

     


    Also X, has CH3 —CH(OH)—, gives iodoform test and it is chiral.

     

     

  • Question 4/9
    1 / -0.25

     

    An organic compound X (C9 H12 O) gives the following reactions :
    i. Na - Slow gas bubble formation
    ii. Acetic anhydride - Pleasent smelling liquid
    iii. CrO3 -H2 SO4 - Blue-green solution
    iv. Hot KMnO4 - Benzoic acid
    v. Br2 -CCI4 - No decolouration
    vi. I2 + NaOH - Yellow solid is formed
    vii. X rotates the plane polarised light

    Q. 

    If X is treated with HCI in the presence of ZnCI2 , the major product would be

     

    Solutions

     

     


    Also X, has CH3 —CH(OH)—, gives iodoform test and it is chiral.
     

     

     

  • Question 5/9
    1 / -0.25

     

    An organic compound X (C9 H12 O) gives the following reactions :
    i. Na - Slow gas bubble formation
    ii. Acetic anhydride - Pleasent smelling liquid
    iii. CrO3 -H2 SO4 - Blue-green solution
    iv. Hot KMnO4 - Benzoic acid
    v. Br2 -CCI4 - No decolouration
    vi. I2 + NaOH - Yellow solid is formed
    vii. X rotates the plane polarised light

    Q. 

    An isomer of X, Y was also found to be optically active. It showed the same reactions as X except (vi). Hence, Y is

     

    Solutions

     

     


    Also X, has CH3 —CH(OH)—, gives iodoform test and it is chiral.

    does not give iodoform test but gives all other reaction similar to X.

     

     

  • Question 6/9
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    One Integer Value Correct Type

    Direction : This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

    An organic compound X (C5 H12 O) is chiral. Also

    Q.

    How many primary hydrogens are present in X?

     

    Solutions

     

     

    X is a primary alcohol as indic ated by Victor Meyer test as well as it has a chiral carbon, hence

     

     

  • Question 7/9
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    An alcohol X (C7 H16 O) gives immediate turbidity with HCI/ZnCI2 and can be resolved into enantiomers. Also X has a tertiary hydrogen. How many CH3 —groups are present in X?

     

    Solutions

     

     

    Compound X satisfying the given criteria is

     

     

  • Question 8/9
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    An alcohol X (C4 H10 O3 ) is chiral and absorbs two moles of HIO4 per mole of X. How many stereoisomers exist for X?

     

    Solutions

     

     

    X satisfying the given criteria is

    Hence, X has four optically active isomers.

     

     

  • Question 9/9
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    An organic compound X (C7 H16 O) gives effervescence with Na. X has both enantiomers and diastereomers. X gives yellow precipitate with alkaline iodine solution. With CrO3 - H2 SO4 , X is converted into C7 H14 O  (Y) which has enantiom ers but not diastereom ers. X on refluxing with H2 SO4 isomerises to Z which neither gives yellow precipitate with alkaline iodine nor changes colour of CrO3 - H2 SO4 . What is the minim um number of carbons that can be present in the parent chain of X ?

     

    Solutions

     

     

    From the give condition, structure of X is derived to be

     

     

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