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Wave Optics Test - 10
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Wave Optics Test - 10
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  • Question 1/8
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    Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

    Assertion : In YDSE number of bright fringe or dark fringe can not be unlimited

    Reason : In YDSE path difference between the superposing waves can not be more than the distance between the slits.

     

    Solutions

     

    Path difference at a point of superposition on the screen at a distance 'y' from the central maxima in YDSE is given by yd/D. Thus y can be any large to form any order of bright or dark fringe. Apparently from the expression of path difference, it can be more than d for large values of y.

     

  • Question 2/8
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    Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

    Assertion : Coloured spectrum is seen when we look through a muslin cloth.

    Reason : It is due to the diffraction of white light on passing through fine slits.

     

    Solutions

     

    When we look through a muslin cloth coloured spectrum cab be seen. Because muslin cloth has fine slits in it. When white light passes through thin fine slits, diffraction occurs. Due to this diffraction of light we can coloured spectrum.

     

  • Question 3/8
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    Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

    Assertion : According to Huygen’s principle, no backward wave-front is possible.

    Reason : Amplitude of secondary wavelet is proportional to (1 + cos θ) where θ is the angle between the ray at the point of consideration and the direction of secondary wavelet.

     

  • Question 4/8
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    Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

    Assertion : No interference pattern is detected when two coherent sources are infinitely close to each other.

    Reason : The fringe width is inversely proportional to the distance between the two sources.

     

    Solutions

     

    When d is negligibly small, fringe width. β which is proportional to 1/d may become too large. Even a single fringe may occupy the whole screen. Hence the pattern cannot be detected.

     

  • Question 5/8
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    Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

    Assertion : White light falls on a double slit with one slit is covered by a green filter. The bright fringes observed are of green colour.

    Reason : The fringes observed are coloured.

     

    Solutions

     

    Interference will take place in green light only

     

  • Question 6/8
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    Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

    Assertion : In Young ’s double slit experiment if wavelength of incident monochromatic light is just doubled, the number of bright fringes on the screen will increase.

    Reason : Maximum number of bright fringe on the screen is inversely proportional to the wavelength of light used

     

    Solutions

     

     

    Wavelength is inversely proportional to the number of fringes, hence by doubling the wavelength the number of fringes decreases. Hence Assertion and reason are false.

     

     

  • Question 7/8
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    Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

    Assertion : Interference pattern is made by using yellow light instead of red light, the fringes become narrower.

    Reason : In YDSE, fringe width is given by β=λD/d

     

    Solutions

     

    The fringe width is given by

    β=λD/d

    The fringe width is directly proportional to the wavelength.

    The wavelength of blue light is less than that of the red light. So, for blue light the fringe will be narrower.

    So, Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

     

     

  • Question 8/8
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    Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

    Assertion : Diffraction takes place for all types of waves mechanical or nonmechanical, transverse or longitudinal.

    Reason : Diffraction’s effects are perceptible only if wavelength of wave is comparable to dimensions of diffracting device.

     

    Solutions

     

    Diffraction is defined as the bending of light around the corners of the obstacle or aperture into the region Of geometrical shadow if the obstacle. Diffraction occurs with all waves, including sound waves, water waves and electromagnetic waves.

     

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