Please wait...

Chemistry Test 178
Menu grid icon
Result Result point icon
Chemistry Test 178
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    4 / -1

    The solubility of CaF2 in pure water is 2.3 × 10-4 mol dm-3. Its solubility product will be

    Solutions

    Solubility product = 4S3

    = 4(2.3 × 10-4)3

    = 4 × 12.167 × 10-12

    = 48.67 × 10-12

    = 4.867 × 10-11 = 4.9 × 10-11

     

  • Question 2/10
    4 / -1

    The solubility of Mg(OH)2 is S moles/litre. The solubility product under the same conditions is

    Solutions

    Ksp = [Mg2+] [OH-]2

    Ksp = S × (2S)2

    Ksp = 4S3

     

  • Question 3/10
    4 / -1

    In the reaction 2H2O (g) + 2Cl2 (g) ⇄ 4HCl (g) + O2 (g), the values of Kp and Kc are related as

    Solutions

    Therefore, KP > KC for those reactions that proceed with an increase in the number of gaseous moles.

    2H2O (g) + 2Cl2 (g) ⇄ 4HCl (g) + O2 (g)

    Kp = KcRT

    So, Kp > Kc

     

  • Question 4/10
    4 / -1

    If the concentration of [Ag+] = 10-5 in a solution, then the concentration of [Cl-] required for the precipitation of AgCl (Ksp = 2 ×10-12) is

    Solutions

    Use the expression: Ksp = [Ag+][Cl-]

    2 × 10-12 = 10-5 × [Cl-]

    [Cl-] = 2 × 10-7

     

  • Question 5/10
    4 / -1

    Which of the following compounds is not a protonic acid?

    Solutions

    Since B(OH)3 is not able to donate any proton, so it is not a protonic acid.

     

  • Question 6/10
    4 / -1

    For a sparingly soluble salt ApBq, the relationship between its solubility product (Ls) and its solubility (S) is

    Solutions

    Ap Bq = pA+ + qB-

    If S is the solubility,

    [A+] = pS, [B-] = qS;

    Ksp = [A+]p[B-]q

    Ls= (pS)p (qS)q = Sp+q pp qq

     

  • Question 7/10
    4 / -1

    What is the maximum concentration of equimolar solution of ferrous sulphate and sodium sulphide, so that when mixed in equal volumes there is no precipitation of iron sulphide? [Ksp for iron sulphide = 6.3 × 10-18]

    Solutions

    Let the concentration of FeSO4 and Na2S be x mol L-1.

    Then, after mixing equal volumes:

    [FeSO4] = [Na2S] = x/2 M

    Or [Fe2+] = [S2-] = x/2 M

    FeS ⇌ Fe2+ + S2-

    Ksp = [Fe2+][S2-]

    6.3 × 10-18 = (x/2)(x/2)

    On solving, x = 5.02 × 10-9 mol L-1

     

  • Question 8/10
    4 / -1

    The solubility product of silver bromide is 5 x 10-13. The quantity of potassium bromide with molar mass 120 g/mol to be added to 1 litre of 0.05 M solution of silver nitrate to start the precipitation of AgBr is

    Solutions

     

  • Question 9/10
    4 / -1

    For the equilibrium A ⇋ B, the variation of the rate of the forward (a) and reverse (b) reaction with time is given by

    Solutions

     

  • Question 10/10
    4 / -1

    The number of H+ ions in 1 cm3 of a solution having pH = 13 is ___________.

    Solutions

    For pH = 13,

    [H+] = 10-13 M

    Number of moles H+ ions in 1000 cm3(1 L) solution = 10-13 

    Number of moles of H+ ions in 1 cm3 solution 

    Number of moles of H+ ions in 1 cm3 solution = Number of moles × 6.023 × 1023

    Number of moles of H+ ions in 1 cm3 solution = 10-16 × 6.023 1023 = 6.023 × 107

     

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now