Please wait...

Electrochemistry Test - 10
Menu grid icon
Result Result point icon
Electrochemistry Test - 10
  • Goals icon

    /

    Score
  • Trophy icon

    -

    Rank
White alarm icon Time Taken: -
Result frame illustration
  • Question 1/10
    1 / -0.25

     

    Calculate the useful work of the reaction Ag(s) + 1/2Cl2 (g) → AgCl(s)
    Given  E °cl2/cl-  = + 1.36 V,    E °AgCl/Ag,Cl-  = 0.22 V

    If     Pcl2   = 1 atm   and T = 298 K

     

    Solutions

     

     

    (1) AgCl (s) + e →Ag(s) + Cl-      E0  = 22 V

    (2) 1/2 Cl2  + e →Cl-        E0   = 1.36V

    we get

    Ag(s) + 1/2Cl2 (g)  →AgCl(s)      E0cell   = 1.14V

     

     

  • Question 2/10
    1 / -0.25

     

    Which of these ions Cu+ , Co3+ , Fe2+  is stable in aqueous medium.

    Given :

    E ° Cu2+ /Cu+  = 0.15 volt ;       E ° Cu+ /Cu  = 0.53 V ;    E ° Co3+ /Co2+  = 1.82 V ;

    E ° Fe3+ /Fe2+  = 0.77 V ;  E ° Fe2+ Fe  = - 0.44 V ;   E ° O2 ,H+ /H2 O  = 1.23 V

     

    Solutions

     

     

     if reduction potential of metal ion is greater then O2 /H2 O couple, the ion is stable in water. So Co3+ is stable in water

     

     

  • Question 3/10
    1 / -0.25

     

    Select the correct statement if -

    E ° Mg2+ /Mg  = - 2.4V,    E ° Sn4+ /Sn2+  = 0.1 V,   E ° MnO4- ,H+ /Mn2+  = 1.5 V, E °  I2 /I-  = 0.5 V   Here,

     

    Solutions

     

     

    [Hint: Reverse of (B) &(C) is spontaneous; weakest Oxidizing Agent here is Mg2+ ]

     

     

  • Question 4/10
    1 / -0.25

     

     What is the value of pKb (CH3 COOH- ) if λm∞  = 390 &λm  = 7.8 for 0.04 of a CH3COOH at 25 °C           

     

    Solutions

     

     

     

     

  • Question 5/10
    1 / -0.25

     

    The temperature coefficient of a standard Cd-cell is –5.0X10–5 Vk–1 whose emf at 25 °C is 1.018 V. During the cell operation, the temperature will -           

     

    Solutions

     

     

     

     

  • Question 6/10
    1 / -0.25

     

     A cell Ag | Ag+ || Cu++ | Cu initially contains 2M Ag+ and 2M Cu++ ions. The charger in cell potential after the passage of 10 amp current for 4825 sec is:          

     

    Solutions

     

     

     

     

  • Question 7/10
    1 / -0.25

     

    For the cell (at 298 K)

    Ag(s) | AgCl(s) | Cl- (aq) || AgNO3 (aq) | Ag(s)

    Which of the following is correct –

     

    Solutions

     

     

    Conductivity is high due to [H+ ]

     

     

  • Question 8/10
    1 / -0.25

     

    During an electrolysis of conc. H2 SO4 , perdissulphuric acid (H2 S2 O8 ) and O2 from in equimolar amount. The amount of H2 that will form simultaneously will be (2H2 SO4 →H2 S2 O8 + 2H+ + 2e- )

     

    Solutions

     

     

     

     

  • Question 9/10
    1 / -0.25

     

    Statement-1:  In electrochemical cell, we cannot use KCI in the salt bridge if anodic  or cathodic compartment consists of Ag+  of Pb2+  ion.

    Statement-2:  Salt bridge is employed to maintain the electrical neutrality and to minimize the liquid-liquid junction potential.

     

    Solutions

     

     

    Both (S –1) &(S –2) are true and (S –2) is not the correct explanation of    (S –1)

     

     

  • Question 10/10
    1 / -0.25

     

    Statement-1: Zinc protect the iron better than tin even after it cracks.

    Statement-2: E°OPzn < E°OPfe But E°OPSn > E°OPfe

    Solutions

     

     

    The correct answer C
    EZn+2∣Zn  < EFe+2∣Fe<E+2Sn∣Sn
       SPR ↓  Reactivity ↑

     

Close button icon
User Profile
-

Correct (-)

Wrong (-)

Skipped (-)

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Mockers logo Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Arrow pointer icon
Click on Allow to receive notifications
Notification bell icon ×
Open Now