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Electrochemistry Test - 11
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Electrochemistry Test - 11
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  • Question 1/10
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    A current of 0.1A was passed for 2hr through a solution cuprocyanide and 0.3745g f copper was deposited on the cathode. Calculate the current efficiency for the copper deposition.

     

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  • Question 2/10
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    With t taken in seconds and I taken in Amp, the variation of I follows the equation

     t2 + I2 = 25

    what amount of Ag will be electrodeposited with this current flowing in the interval 0-5 second ? (Ag : 108)

     

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    =21.97mg = 22mg

     

     

  • Question 3/10
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    A resistance of 50 Ω is registered when two electrodes are suspended into a beaker containing a dilute solution of a strong electrolyte such that exactly half of the them are submerged into solution. If the solution is diluted by adding pure water (negligible conductivity) so as to just completely submerge the electrodes, the new resistance offered by the solution would be

     

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    the k is halved while the A is doubled. Hence R remain 50  Ω.

     

     

  • Question 4/10
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    The standard reduction potential of a silver chloride electrode is 0.2 V and that of a silver electrode is 0.79 V. The maximum amount of AgCl that can dissolve in 106 L of a 0.1 M AgNO3 solution is           

     

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  • Question 5/10
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    Calculate the cell EMF in mV for

    Pt|H2 (1atm) |HCl(0.01M)|AgCl(s)| Ag(s)        at 298 K

     If ΔG °r values are at 25 °C

     for AgCl(s) and    for H+  + Cl- ) (aq)

     

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  • Question 6/10
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    Adiponitrile is manufactured electrolytically from acrylonitrile

     CH2 = CHCN → CN –(CH2 )4 –CN

    How many kg of adiponitrile (molecular mass = 108) is produced in 9.65 hr using a current of 3750 A with 80% efficiency

     

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  • Question 7/10
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    It is observed that the voltage of a galvanic cell using the reaction M(s) + xH+ → Mx+ + X/2H2 varies linearly with the log of the square root of the hydrogen pressure and the cube root of the Mx+ concentration. The value of x is     

     

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  • Question 8/10
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    Acetic acid has Ka = 1.8 X  10 –5 while formic acid had Ka = 2.1 X  10–4 . What would be the magnitude of the emf of the cell

     

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  • Question 9/10
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    Consider the cell Ag(s)|AgBr(s)|Br-(aq)||AgCl(s)|Cl-(aq)|Ag(s) at 25 °C. The solubility product constants of AgBr &AgCl are respectively 5 X  10 –13 &1 X  10 –10 . For what ratio of the concentrations of Br- &Cl- ions would the emf of the cell be zero ?           

     

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  • Question 10/10
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    Value of  for SrCl2 in water at 25 °C from the following data:

     

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