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Find the equation of the line passing through the intersection of the lines x + 2y - 3 = 0 and 4x – y + 7 = 0 and which is parallel to y – x + 10 = 0.
Let the equation be x + 2y - 3 + k (4x - y + 7) = 0 ............ (i)
i.e., (1 + 4k) x + (2 - k) y + 7k - 3 = 0
i.e., y = (-1 - 4k)/(2-k) + 3 - 7k
Since it is parallel to y - x + 10 = 0 (i.e., y = x - 10), slopes are equal.
So, (- 1 - 4k)/(2 - k) = 1
- 1 - 4k = 2 - k
k = - 1
Substituting this in eq (i), we get:
The required line is x + 2y - 3 + (-1)(4x - y + 7) = 0
i.e. - 3x + 3y - 10 = 0
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⇒ |3 – r| < 5 < 3 + r⇒ 2 < r < 8
Let f(x) = sin x + cos x. Then,
The sides of the rectangle of the greatest area, that can be inscribed in the ellipse x2 + 2y2 = 8, are given by
(1) f(x) has one point of inflexion.
(2) g(x) has one point of inflexion.
(3) f(x) has one point of local minima.
(4) g(x) has one point of local maxima.
Which one of the following is correct regarding the above statements?
(1) is true. (2) is false.
(1) is false. (2) is true.
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