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Physics Test 180
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Physics Test 180
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  • Question 1/10
    4 / -1

    Plane angle and solid angle have

    Solutions

     

  • Question 2/10
    4 / -1

    The physical quantity that has the same dimensional formula as pressure is:

    Solutions

     

  • Question 3/10
    4 / -1

    If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy.

    Solutions

    Energy, E ∝ Fa AbTc

    [E] = [Fa][Ab][Tc]

    ⇒ [ML2T−2] = [MLT−2]a[LT−2]b[T]c

    [ML2T−2] = [MaLa+bT−2a−2b+c]

    Comparing dimensions on both sides.

    ⇒ a = 1 ; a + b = 2 and −2 = −2a − 2b + c

    ⇒ b = 1 ⇒ −2 = −2 −2 + c

    ⇒ c = 2

    [E] = [F AT2]

     

  • Question 4/10
    4 / -1

    If E and G respectively denote energy and gravitational constant, then E/G has the dimensions of

    Solutions

     

  • Question 5/10
    4 / -1

    Taking into account of the significant figures, what is the value of 9.99m − 0.0099m?

    Solutions

    In subtraction the number of decimal places in the result should be equal to the number of decimal places of that term in the operation which contain lesser number of decimal places.

    9.99 − 0.0099 = 9.9801

    As the least number of decimal places is 3.

    So, answer should be 9.98m.

     

  • Question 6/10
    4 / -1

    The unit of thermal conductivity is.

    Solutions

    where Q is the amount of heat flow, x is the thickness of the slab, A is the area of cross-section, and t is the time taken.

     

  • Question 7/10
    4 / -1

    The main scale of a vernier callipers has n divisions/cm. n divisions of the vernier scale coincide with (n-1) divisions of main scale. The least count of the vernier callipers is,

    Solutions

    If nth division of vernier scale coincides with (n − 1) divisions of main scale.

    Therefore, nV SD = (n − 1)MSD

     

  • Question 8/10
    4 / -1

    A physical quantity of the dimensions of length that can be formed out of c, G and  is [c is velocity of light, G is the universal constant of gravitation and e is charge].

    Solutions

     

  • Question 9/10
    4 / -1

    If dimensions of critical velocity vc of a liquid flowing through a tube are expressed as [ηxρyγz] where η, ρ and γ are the coefficient of viscosity of liquid, density of liquid and radius of the tube respectively, then the values of x, y and z are given by.

    Solutions

    [vc] = [ηxρyγz] (given) ........(i)

    Writing the dimensions of various quantities in eqn. (i), we get

    [M0LT−1] = [M L−1T−1]x [M L−3T0]y[M0 LT0]z

    = [Mx+yL−x−3y+zT−x]

    Applying the principle of homogeneity of dimensions, we get

    x + y = 0; −x − 3y + z = 1; −x = −1

    On solving, we get x = 1, y = −1, z = −1

     

  • Question 10/10
    4 / -1

    In an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively. Quantity P is calculated as follows

    Solutions

     

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