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Mathematical Ability Test-4
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Mathematical Ability Test-4
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  • Question 1/10
    1 / -0

    To dispose of the old stocks, a person sold a tea-set for Rs 3,540, which was 41% below the cost price. To make a profit of 11%, the seller should have sold the set for ____ more.

    Solutions

     

  • Question 2/10
    1 / -0

    In the given figure ∠QPR = 60°. If OQ and OR are the angle bisectors of ∠Q and ∠R, then find the value of ∠QOR.

    Solutions

    Given:

    ∠QPR = 60° 

    OQ and OR are the bisector of ∠Q and ∠R.

    According to the formula used,

     

  • Question 3/10
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    The polar coordinates of the vertices of a triangle are  Then, the triangle is:

    Solutions

     

  • Question 4/10
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    Solutions

     

  • Question 5/10
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    What is the value of tan 75° + cot 75°?

    Solutions

     

  • Question 6/10
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    In formula Mean deviation = MD = (1/n) ∑|x − M| what does M indicates:

    Solutions

    The mean deviation is the sum of the deviations from the average divided by the number of items in the series.

     

  • Question 7/10
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    A man purchased an old typewriter at Rs 19200, and spent some amount on its repair. He sold it for Rs 24150, and earned a profit of 15%. Find the amount he spend on the repair of the old typewriter.

    Solutions

    ⇒ 19200 + x = 21000

    ⇒ x = 21000 – 19200

    ⇒ x = 1800

    ∴ The amount spend on repairing of old typewriter is Rs 1800.

     

  • Question 8/10
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    Find the equation of ellipse whose eccentricity is 1/2, length of latus rectum is 4 and the center is (0,0).

    Solutions

     

  • Question 9/10
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    If the length of a certain rectangle is decreased by 4 cm and the width is increased by 3 cm, a square with the same area as the original rectangle would result. Find the perimeter of the original rectangle.

    Solutions

    Given

    length of a rectangle is decreased by 4 cm and the width is increased by 3 cm

    Formula used:

    Area of rectangle = (l × b) sq. unit and Area of square = (side)2 sq. unit 

    Perimeter of rectangle = 2(l + b) units

    Let the length and breadth of the rectangle be x and y 

    ⇒ Area of rectangle = (l × b) sq. unit

    ⇒ xy cm2

    ⇒ new length and breadth = (x - 4) and (y + 3)

    ⇒ (x - 4) = (y + 3)

    ⇒ x - y = 7 .....(1)

    ⇒ Area of square = (x - 4) × (y + 3)

    According to question

    ⇒ Area of rectangle = Area of square 

    ⇒ xy = (x - 4) × (y + 3)

    ⇒ 3x - 4y = 12 .....(2)

    ⇒ On solving these equation 

    ⇒ x = 16 and y = 9

    ⇒ Perimeter of rectangle = 2(l + b) units

    ⇒ 2(16 + 9)

    ⇒ 2 × 25

    ⇒ 50 cm

    ∴ perimeter of the original rectangle is 50 cm

     

  • Question 10/10
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    The HCF of two numbers a and b is c. What is the LCM of those two numbers?

    Solutions

     

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