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Chemistry Test 258
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Chemistry Test 258
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  • Question 1/10
    4 / -1

    In graphite and diamond, the percentage of p-characters of the hybrid orbital in hybridisation is respectively:

    Solutions

  • Question 2/10
    4 / -1

    Which of the following conversions involves change in both shape and hybridisation?

    Solutions

    The hybridisation in boron atom changes from sp2 to sp3 in the following conversion:

    BF3 → BF-4

     

  • Question 3/10
    4 / -1

    Which of the following lines correctly show the temperature dependence of equilibrium constant K for an exothermic reaction?

    Solutions

     

  • Question 4/10
    4 / -1

    An aqueous solution contains 0.10 M H2S and 0.20 M HCI. If the equilibrium constant for the formation of HS- from H2S is 1 .0 x 10-7 and that of S2- from HS- ions is 1.2 x 10-13, then the concentration of S2- ions in aqueous solution is

    Solutions

     

  • Question 5/10
    4 / -1

    Which of the following is not a property of physical adsorption?

    Solutions

    Physical adsorption is multilayer adsorption. Monolayer is formed in case of chemisorption.

     

  • Question 6/10
    4 / -1

    The major product of the following reaction is:

    Solutions

     

  • Question 7/10
    4 / -1

    Peroxyacetyl nitrate (PAN), an eye irritant is produced by:

    Solutions

    Photochemical smog produce chemicals such as formaldehyde, acrolein and peroxyacetyl nitrate (PAN).

     

  • Question 8/10
    4 / -1

    Which of the following compounds is metallic and ferromagnetic?

    Solutions

    Chromium Oxide (CrO2) is metallic compound and it shows Ferromagnetic property. It is a black synthetic magnetic solid and was once widely used in magnetic tape emulsion.

     

  • Question 9/10
    4 / -1

    The major product formed in the following reaction is:

    Solutions

    PCC oxidises 1° and 2° alcohols into aldehyde and ketones, respectively.

     

  • Question 10/10
    4 / -1

    The hybridization of the central atom in SF6 is:

    Solutions

    The hybridisation of the central atom in SF6 is sp3d2. Here’s why:

    • The sulphur atom in SF6 forms six bonds with fluorine atoms.
    • To accommodate six bonds, sulphur uses one s orbital, three p orbitals, and two d orbitals.
    • This results in sp3d2 hybridisation, giving SF6 an octahedral shape.

     

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