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Chemistry Test 262
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Chemistry Test 262
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  • Question 1/10
    4 / -1

    Name the end product in the following series of reactions

    Solutions

     

  • Question 2/10
    4 / -1

    Which of the following does not illustrate the anomalous properties of lithium?

    Solutions

    The strength of the metallic bond decreases down the group. The hardness of these alkali metals decreases down the group. Hence, 'Li' is harder than other alkali metals.

     

  • Question 3/10
    4 / -1

    The vapour of Hg absorb some electrons accelerated by a potential difference of 4.5 volts from rest as a result of which light is emitted. If the full energy of a single incident electron is supposed to be converted into light emitted by electron in a single Hg atom, find the wave number (1/λ) of the light

    Solutions

    Potential difference 4.5 V

    ∴ Potential energy = 4.5 eV energy absorbed and this energy is emitted by electron of Hg atom.

     

  • Question 4/10
    4 / -1

    Identify the correct statement:

    Solutions

    Corrosion of iron can be minimised by forming a contact with another metal with a lower reduction potential. Corrosion of iron can be minimised by forming an impermeable barrier at its surface.

     

  • Question 5/10
    4 / -1

    A crystalline hydrated salt on being heated loses 45.6% of its weight. Percentage composition of anhydrous salt is Al - 10.5 %, K - 15.1 %, S - 24.8 %, O - 49.6 %. Find molecular formula of salt (hydrated) (M = 948 g/mol for hydrated salt).

    Solutions

     

  • Question 6/10
    4 / -1

    Which one of the following ores is best concentrated by froth flotation method?

    Solutions

    Froth flotation method is used for concentration of sulphide ores.

    Galena → PbSGalena → PbS

    Malachite is Cu2(CO3)2(OH)2

    Magnetite is Fe3O4

    Siderite is FeCO3

     

  • Question 7/10
    4 / -1

    Which of the following is a biradical?

    Solutions

     

  • Question 8/10
    4 / -1

    At 500 K, the half life period of a gaseous reaction at an initial pressure of 80 kPa is 350 s350 s. When the pressure is 40 kPa, the half life period is 175 s; the order of the reaction is :

    Solutions

     

  • Question 9/10
    4 / -1

    Consider the following three halides :

    (1) CH3 − CH2 − Cl

    (2) CH2 = CH − Cl

    (3) C6H5 − Cl

    Arrange C − Cl bond length of these compounds in decreasing order -

    Solutions

    The C–Cl bond length depends on the hybridization of the carbon atom bonded to the chlorine atom. The greater the s-character of the hybrid orbital in the carbon, the shorter the C–Cl bond length.

    1. Compound (1): CH₃–CH₂–Cl

      • The carbon bonded to chlorine is sp³-hybridized (single bond).
      • An sp³-hybridized carbon has the least s-character (25%), resulting in the longest bond length.

    2. Compound (2): CH₂=CH–Cl

      • The carbon bonded to chlorine is sp²-hybridized (double bond).
      • An sp²-hybridized carbon has 33% s-character, leading to a shorter C–Cl bond than sp³.

    3. Compound (3): C₆H₅–Cl (chlorobenzene)

      • The carbon bonded to chlorine is sp²-hybridized, but it is part of the benzene ring.
      • Due to resonance in the benzene ring, the C–Cl bond has partial double bond character, making it the shortest bond length among the three.

    Conclusion: The bond length order is:

    Compound (1) > Compound (2) > Compound (3).

    Thus, the correct answer is (a) 1 > 2 > 3.

     

  • Question 10/10
    4 / -1

    Ratio of ΔTb/Kb of 10 g AB2 and 14 g A2B per 100 g of solvent in their respective, solution (AB2 and A2B both are non-electroytes) is 1 mol/kg in both cases. Hence, atomic weight of A and B are respectively :

    Solutions

     

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