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Chemistry Test 266
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Chemistry Test 266
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  • Question 1/10
    4 / -1

    0.5 molal solution acetic acid (M.W. = 60) in benzene (M.W. = 78) boils at 80.80 °C. The normal boiling point of benzene is 80.10 °C and Δvap H = 30.775 KJ/mol. Which of the following option is correct regarding percent of association of acetic acid in benzene.

    Solutions

    Given to (boiling point of benzene) = 80.10 °C = 353.1K molality (m) = 0.5

     

  • Question 2/10
    4 / -1

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  • Question 3/10
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  • Question 4/10
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  • Question 5/10
    4 / -1

    [X3B ← NH3], in which of the following boric halide, tendency to accept electrons from nitrogen of ammonia will be least (X = halogens)

    Solutions

    In BF3, due to F back bonding to B, least Lewis acid character is observed. So out of above four, BF3 will have least tendency to accept electron from NH3.

    Hence, option (D) is correct.

     

     

  • Question 6/10
    4 / -1

    E1, E2 and E3 are activation energies then, which of the following is correct.

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  • Question 7/10
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  • Question 8/10
    4 / -1

    For a gas obeying the van der waals equation at critical temperature, which of the following is true.

    Solutions

    At critical point only one phase exits. Graph appears as given below

    There is a stationary inflection point in PV Diagram (at a given critical temperature)

     

  • Question 9/10
    4 / -1

    X + HNO3→ Y + NO2 + H2O + S Y + ammonium molybdate → yellow ppt.

    Identity which of the following is (X):

    Solutions

    As2S5 + HNO3→ H3AsO4 + NO2 + H2O + S

    H3ASO4 + (NH4)2MoO4→(NH4)24sO4 12MoO3

    Yellow ppt.

    Hence option (A) correct

     

  • Question 10/10
    4 / -1

     Oleum in water is treated with 0.5l of 2.75 M Ca(OH)2 solution. The resulting solution required 15.7 gm of H3PO3 (Assume strong acid) solution for complete neutralization. Calculate the amount of free SO3 in 100 gms of oleum

    Solutions

     

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