NEET Test 188

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NEET Test 188

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Question 1/10
4 / -1

Two solutions of a substance are mixed in the following manner: 480 mL of 1.5 M first solution +520 mL of 1.2 M second solution. What is the molarity of the final mixture?

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A
1.20 M

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B
1.50 M

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C
1.344 M

Correct

Wrong

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D
2.70 M

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Solutions
Question 2/10
4 / -1

Two particles execute SHM of the same amplitude and frequency along the same straight line. If they pass each other when going in opposite directions, each time their displacement being half their amplitude, the phase difference between them is

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A

Correct

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B

Correct

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C

Correct

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D

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Solutions
Question 3/10
4 / -1

A person can see clearly only upto a distance of 25 cm. He wants to read a book placed at a distance of 50 cm from his eyes. What is the power of the lens of his spectacles?

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A
−1.0D

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B
−1.33D

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C
−1.67D

Correct

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D
−2D

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Solutions

For correcting myopia, a concave lens is used and for the lens.
Question 4/10
4 / -1

Which of the following is the most frequently used techniques in DNA fingerprinting?

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A
VNTR

Correct

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B
SSCP

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Wrong

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C
AFLP

Correct

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D
None of these

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Solutions

VNTRs are an important source of RFLP genetic markers used in linkage analysis (mapping) of genomes. They have become essential in forensic crime investigations. The technique may use PCR, size determined by gel electrophoresis, and Southern blotting to produce a pattern of bands unique to each individual.
Question 5/10
4 / -1

A resonance air column of length 40 cm resonates with a tuning fork of frequency 450 Hz. Ignoring end corrections, the velocity of sound in air will be:

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A
1020 m/s

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B
920 m/s

Correct

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C
820 m/s

Correct

Wrong

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D
720 m/s

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Solutions

We know that the minimum length of the air column tube corresponds to the fundamental mode of vibrations. Hence, by ignoring end corrections-
Question 6/10
4 / -1

What is not applicable to ozone?

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A
It is a bent molecule with bond angle approximately 117^∘

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B
It has four lone pairs of electrons in one of its Lewis formula

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C
The two O − O bond lengths are equal

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D
It is an allotrope of oxygen.

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Solutions

Ozone is an allotrope of oxygen and it is a bent molecule with bond angle approximately 117^∘. it is having 6 lone pairs. In it O − O bond length are equal due to resonance.
Question 7/10
4 / -1

Which of the following statements is incorrect?

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A
In the dicot root, the vascular cambium is completely secondary in origin.

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B
Wood is the common name used for secondary xylem.

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C
A mature sieve tube element lacks peripheral cytoplasm, a large vacuole, and a prominent nucleus.

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D
Lenticels are the aerating pores present in the bark of plants and are associated with the gaseous exchange.

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Solutions

A mature sieve element possesses a peripheral cytoplasm and a large vacuole but lacks a nucleus. The functions of sieve tubes are controlled by the nucleus of companion cells.
Question 8/10
4 / -1

Zinc is essential for:

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A
Biosynthesis of chlorophylls

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B
Biosynthesis of 3 − IAA

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C
Stomatal closing

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D
Oxidation of carbohydrates

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Solutions

Plants obtain zinc as Zn²⁺ ions. It activates various enzymes, especially carboxylases. It is also needed in the synthesis of auxin. Indole-3-acetic acid (3−IAA) is the most common naturally occurring plant hormone of the auxin class.
Question 9/10
4 / -1

Calculate the molarity of a solution containing 5g of NaOH in 1 L solution.

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A
0.125 mol L⁻¹

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B
0.275 mol L⁻¹

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C
0.375 mol L⁻¹

Correct

Wrong

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D
None of the above

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Solutions
Question 10/10
4 / -1

In the given circuit, the potential difference across PQ will be nearest to

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A
9.6 V

Correct

Wrong

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B
6.6 V

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C
4.8 V

Correct

Wrong

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D
3.2 V

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Solutions

Question 1/10

1.20 M

1.50 M

1.344 M

2.70 M

Question 2/10

Question 3/10

−1.0D

−1.33D

−1.67D

−2D

Question 4/10

VNTR

SSCP

AFLP

None of these

Question 5/10

1020 m/s

920 m/s

820 m/s

720 m/s

Question 6/10

It is a bent molecule with bond angle approximately 117∘

It has four lone pairs of electrons in one of its Lewis formula

The two O − O bond lengths are equal

It is an allotrope of oxygen.

Question 7/10

In the dicot root, the vascular cambium is completely secondary in origin.

Wood is the common name used for secondary xylem.

A mature sieve tube element lacks peripheral cytoplasm, a large vacuole, and a prominent nucleus.

Lenticels are the aerating pores present in the bark of plants and are associated with the gaseous exchange.

Question 8/10

Biosynthesis of chlorophylls

Biosynthesis of 3 − IAA

Stomatal closing

Oxidation of carbohydrates

Question 9/10

0.125 mol L−1

0.275 mol L−1

0.375 mol L−1

None of the above

Question 10/10

9.6 V

6.6 V

4.8 V

3.2 V

It is a bent molecule with bond angle approximately 117^∘

0.125 mol L⁻¹

0.275 mol L⁻¹

0.375 mol L⁻¹