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Solutions
Given,
KE1 = 50J
KE2 = 150J
t = 10s
As we know,
The work-energy theorem states that the net work done by the forces on an object is equal to the change in its kinetic energy.
W = ΔKE
Where W = work done and ΔKE = change in kinetic energy
By the work-energy theorem,
W = ΔKE
∴ W = KE2 − KE1
⇒ W = 150 − 50
⇒ W = 100J
So, the power of the body (P) = W/t
Where W = work and t = time
∴ P = 100/10
⇒ P = 10W