The correct answer is Option B.

The C-C-C bond angles in cyclopropane (60^o) and cyclobutane (90^o) are much different than the ideal bond angle of 109.5^o.This bond angle causes cyclopropane and cyclobutane to have a high ring strain. However, molecules, such as cyclohexane and cyclopentane, would have a much lower ring strain because the bond angle between the carbons is much closer to 109.5^o.

The correct answer is option D

Cyclopropane is a cycloalkane molecule with the molecular formula C₃H₆, consisting of three carbon atoms linked to each other to form a ring, with each carbon atom bearing two hydrogen atoms resulting in D₃H molecular symmetry. The small size of the ring creates substantial ring strain in the structure.

Priority of functional groups is

- COOH > - CHO >>C = O.

Hence, the lUPAC name is 4-formyl-2-oxocyclohexane carboxylicacid.

CH₃F - sp³ hybridised carbon, tetrahedral shape

(ii) HC = N - sp hybridised carbon, linear shape.

• Both have all their C—C bonds of equal length due to conjugation.
• I does not decolorises brown colour of bromine water solution but II does as The π bonds in Cyclooctatetraene (Compound II) react as usual for olefins, rather than as aromatic ring systems.
• I is planar but II is not as it adopts a tub conformation.
• Cyclooctatetraene shows various other addition reactions including Sulfonation.

Hence, Option A, B and C are correct.

1-3-5-7-cyclooctatetraene it has 8 pi electrons, and like stated above, fits the criteria of 4n, to be antiaromatic. to avoid this state of anti-aromaticity (less stable then expected), it becomes non-planar, so it can be more stable then it would be in the antiaromatic state. cyclooctatetraene can do this because it can fold, however other 6 carbon compounds that have 4n electrons and are planar can not and result in an antiaromatic compound.

Potassium cyclooctatetraene is formed by the reaction of cyclooctatetraene with potassium metal:

2 K + C8H8 → K2C8H8

The reaction entails 2-electron reduction of the polyene and is accompanied by a color change from colorless to brown.

Metals like Potassium tend to loose their own electrons and the excess electrons will complete the aromaticity of the system.Thus, Deprotonation of the above compound converts it into an aromatic anion witn 6 pi electrons.

R − C^δ = N^δ: has electrophilic C-atom and nucleophilic N-atom.