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Chemistry Test 10
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Chemistry Test 10
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  • Question 1/8
    4 / -1

    Boiling point of H2O is higher than that of H2S, because the former

    Solutions

    In H2S, the H-bonding is not effective due to large size and small electronegativity of sulphur in comparison to oxygen. 
    Hence, option A is correct.

     

  • Question 2/8
    4 / -1

    Which of the following is stable to heat?

    Solutions

    Carbonates of alkali metals are stable to heat 

    Hence, option B is correct.

     

  • Question 3/8
    4 / -1

    The diagonal relationship of boron is with

    Solutions

    Boron is Group 13 , period 2 element, so its diagonal relationship with group 14, period 3 element, which is silicon (both are semimetals)

     

  • Question 4/8
    4 / -1

    The oxide that gives hydrogen peroxide on treatment with a dilute acid is

    Solutions

    Na2O2 is sodium peroxide. This gives H2O2 with dilute acid 
    Hence, option B is correct.

     

  • Question 5/8
    4 / -1

    When molten sulphur is suddenly cooled by pouring into water, it takes the form of

    Solutions

    Plastic sulphur is an allotropic form of sulphur.

     

  • Question 6/8
    4 / -1

    Yellow oils of sulphur is/are

    Solutions

    H2S2, H2S3 are Yellow oils of sulphur.

     

  • Question 7/8
    4 / -1

    The compound which gives off oxygen on moderate heating is

    Solutions

    Mercuric oxide decomposes quickly so it gives off oxygen on moderate heating while other oxides are fairly stable.

    2HgO → 2Hg + O2

     

  • Question 8/8
    4 / -1

    Which of the following forms stable dinuclear ions?

    Solutions

    Hg is unique in forming stable dinuclear ions, the two Hg atoms are bonded together using the 6s orbital e.g. [Hg2]Cl2. The dinuclear ion formed by only other metal Zn and Cd are unstable.

     

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