Verify mobile number to view the solution
Solutions
P(AB) = P(1) + P(2) – P(AB)
∴ 1 ≥ P(1) + P(2) – P(AB) ≥ 3/4
P(1) + P(2) – 1/8 ≥ 1/8 ≥ 3/4 (since min. value of P(AB) = 1/8)
P(1) + P(2) ≤ 1/8 + 3/4 = 7/8
As the max. value of P(AB) = 3/8, we get
1 ≥ P(1) + P(2) – 3/8
P(1) = P(2) ≤ 1 + 3/8 = 11/8.
Hence, option D is correct.