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Rotational Motion Test - 4
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Rotational Motion Test - 4
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    In an arrangement four particles, each of mass 2 gram are situated at the coordinate points (3, 2, 0), (1, –1, 0), (0, 0, 0) and (–1, 1, 0). The moment of inertia of this arrangement about the Z-axis will be-

    Solutions

    For particle 1 Iz = Ix + Iy 
    = mrx2 + mry2 
    = m(rx2 + ry2) 
    = 2(32 + 22) = 26 unit 
    For particle 2, m [12 + (–1)2] = 2 × (2) = 4 unit 
    For particle 3, m[12 + 12] = 2 × (2) = 4 unit 
    For particle 4, m (0) = 0 
    Total inertia = 26 + 4 + 4 = 34 unit

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