Chemistry Test 15

Result

Chemistry Test 15

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Question 1/5
4 / -1

In X-H---Y,X and Y both are electronegative elements:

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A
Electron density on X will increase and on H will decrease

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B
In both electron density will increase

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C
In both electron density will decrease

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D
On X electron density will decrease and on H increase

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Solutions

In X - H ----- Y, X-H is a covalent bond and Y-H is a weak electrostatic interaction (kind of H-bonding) . So electron density increases on X as it is electronegative element and decreases on H whereas electrostatic is mere an interaction between ions.
Question 2/5
4 / -1

Bond order of 2.5 is shown by-

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A
O₂^2-

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B
O₂

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C
O₂⁺

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D
O₂^-

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Solutions

bond order is- 1/2 [N_a-N_b]
Bond order of O₂^2- is 1/2 [10-8] =1
bond order of O₂ is 1/2 [10-6] =2
bond order of O₂⁺ is 1/2 [10-5] =2.5
bond order of O₂^- is 1/2 [10-7] =1.5
Question 3/5
4 / -1

Which of the following molecule do not exist-

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A
H₂^-

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B
He₂⁺

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C
Ne₂

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D
F₂

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Solutions

bond order is- 1/2 [N_a-N_b]
bond order of H₂^- is 1/2 [2-1] =0.5
bond order of He₂⁺ is 1/2 [2-1] =0.5
bond order of Ne₂ is 1/2 [10-10] =0
bond order of F₂ is 1/2 [10-8] =1
since bond order of Ne₂ comes out to be zero, hence it is unstable and does not exist.
Question 4/5
4 / -1

Which of the following is not a correct statement?

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A
The electron deficient molecules can act as Lewis acids.

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B
The canonical structures have no real existence.

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C
Every AB₅ molecule does in fact have square pyramidal structure.

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D
Multiple bonds are always shorter than corresponding single bonds.

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Solutions

Every AB₅ molecule does not have square pyramidal structure . This is because such molecules may have trigonal bipyramidal structure due to sp³d hybridisation. Eg: PCl₅ is trigonal bipyramidal in shape.
Question 5/5
4 / -1

The hybridisations of atomic orbitals of nitrogen in NO, NO₃ and NH₃ respectively are

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A
sp, sp³ and sp²

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B
sp², sp³ and sp

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C
sp², sp² and sp³

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D
sp², sp and sp³

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Solutions

Hybridisation =1/2[number of valence electron on central atom + number of monovalent atoms around central atom + charge on anion - charge on cation]

NO= 1/2[5]=2.5 = sp² hybridisation
NO₃= 1/2[5]=2.5= sp² hybridisation
NH₃= 1/2[5+3] =4= sp³ hybridisation

Question 1/5

Electron density on X will increase and on H will decrease

In both electron density will increase

In both electron density will decrease

On X electron density will decrease and on H increase

Question 2/5

O₂^2-

O₂

O₂⁺

O₂^-

Question 3/5

H₂^-

He₂⁺

Ne₂

F₂

Question 4/5

The electron deficient molecules can act as Lewis acids.

The canonical structures have no real existence.

Every AB₅ molecule does in fact have square pyramidal structure.

Multiple bonds are always shorter than corresponding single bonds.

Question 5/5

sp, sp³ and sp²

sp², sp³ and sp

sp², sp² and sp³

sp², sp and sp³

Question 1/5

Electron density on X will increase and on H will decrease

In both electron density will increase

In both electron density will decrease

On X electron density will decrease and on H increase

Question 2/5

O22-

O2

O2+

O2-

Question 3/5

H2-

He2+

Ne2

F2

Question 4/5

The electron deficient molecules can act as Lewis acids.

The canonical structures have no real existence.

Every AB5 molecule does in fact have square pyramidal structure.

Multiple bonds are always shorter than corresponding single bonds.

Question 5/5

sp, sp3 and sp2

sp2, sp3 and sp

sp2, sp2 and sp3

sp2, sp and sp3

O₂^2-

O₂

O₂⁺

O₂^-

H₂^-

He₂⁺

Ne₂

F₂

Every AB₅ molecule does in fact have square pyramidal structure.

sp, sp³ and sp²

sp², sp³ and sp

sp², sp² and sp³

sp², sp and sp³