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Chemistry Test 19
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Chemistry Test 19
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  • Question 1/9
    4 / -1

    Directions For Questions

    Statement 1: Nitrogen can successfully form pπ–pπbonds with different elements with a small size and high electronegativity. 

    Statement 2: Nitrogen is smaller in size. 

    ...view full instructions


    Which of the following statements is correct?

    Solutions

    Nitrogen, being smaller in size, can successfully form pπ–pπbonds with different elements having a small size and high electronegativity. For example- nitrogen can easily form pπ–pπ bonds with oxygen, carbon and fluorine.

  • Question 2/9
    4 / -1

    The correct increasing order of melting points of C, Ge, Si and Pb is

    Solutions

    The melting point of carbon is extremely high. All the elements of group 14 possess diamond-type lattice structure which is highly stable in nature. The process of melting results in the breakage of these highly stable lattice structures. Hence, a large energy is required for the breakage. Down the group, size increases and bond energy of M-M decreases which leads to the decrease in the melting point. Hence, the correct order of increasing melting point is Pb < Ge < Si < C.

  • Question 3/9
    4 / -1

    Directions For Questions

    Statement 1: SiCl4 can undergoes hydrolysis but CCl4 cannot.

    Statement 2: Non-availability of vacant d orbitals in carbon. 

    ...view full instructions


    Which of the following statements is correct?

    Solutions

    Due to non-availability of vacant d-orbitals, carbon cannot exceeds its coordination number to more than four. Thus, CCl4 cannot undergoes hydrolysis.

  • Question 4/9
    4 / -1

    Fluorine always exhibits the -1 oxidation state in its compounds because it has the

    Solutions

    The oxidation state of fluorine in its compound is always –1 while other elements exhibit a large number of oxidation states (–1, +1, +3, +5, +6, +7). This is because fluorine has the highest electronegativity, so it can never exhibit positive oxidation state.

  • Question 5/9
    4 / -1

    Directions For Questions

    Statement 1: Boron forms only covalent compounds.

    Statement 2: Group 13 members form both ionic and covalent compounds. 

    ...view full instructions


    Which of the following statements is correct?

    Solutions

    Both the statements are true but they have no relation with each other. Boron forms only covalent compounds due to its exceptionally small size while all other members of group 13 form both ionic and covalent compounds.

  • Question 6/9
    4 / -1

    Directions For Questions

    Statement 1:Fluorine is the most reactive element among the halogens.

    Statement 2: Fluorine has the lowest bond enthalpy. 

    ...view full instructions


    Which of the following statements is correct?

    Solutions

    Fluorine is the most reactive among halogens due to its highest electronegativity. It has not the lowest bond enthalpy. Iodine has the lowest bond enthalpy.

  • Question 7/9
    4 / -1

    Among the VA (15) group elements one of them forms a compound sold under the name ‘Pearl White’. The element used is

    Solutions

    Bismuth is an element that forms  bismuth oxychloride which is sold under the name ‘Pearl White’.

  • Question 8/9
    4 / -1

    The natures of carbides of beryllium and calcium are respectively

    Solutions

    Carbides of Be are covalent whereas carbides of other members are ionic. This is because beryllium has the smallest size due to which it forms covalent carbides.

  • Question 9/9
    4 / -1

    Directions For Questions

    Statement 1: Fluorine is the strongest oxidizing agent.

    Statement 2: Fluorine has the highest electronegativity. 

    ...view full instructions


    Which of the following statements is correct?

    Solutions

    Fluorine is the strongest oxidizing agent due to its highest electronegativity and electron affinity.

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