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BioMolecules (Carbohydrates & Amino acids) Test - 2
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BioMolecules (Carbohydrates & Amino acids) Test - 2
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  • Question 1/6
    1 / -0

    Which of the following statement(s) is (are) true?

    (i) All amino acids contain one chiral center.

    (ii) Some amino acids contain one, while some contain more chiral center or even no chiral center.

    (iii) All amino acids found in proteins have L configuration.

    (iv) All amino acids found in proteins have 1° amino group.

    Solutions

    Although D-alanine is a constituent of bacterial cell walls, it is not found in proteins.

    The correct answer is: (ii) & (iii)

     

  • Question 2/6
    1 / -0

    Statement-1Reducing sugars undergo mutarotation.

    Statement-2 : During muarotation, one pure anomer is converted into an equilibrium mixture of two anomers.

    Solutions

    One pure anomer of reducing sugars is converted into an equilibrium mixture of two anomers.

    The correct answer is: Both Statement-1 and Statement-2 are true and Statement-2 is the correct explanations of Statement-1.

  • Question 3/6
    1 / -0

    What is the nature of carboxylic group in the solid glycine?

    Solutions

    In solid state, amino acids exist as zwitterions, which contain −NH+3 (acidic in nature) and COO (basic in nature).

    The correct answer is: basic

  • Question 4/6
    1 / -0

    The number of dipeptides possible from two molecules of a typical α-amino acid is

    Solutions

    Two molecules of an α-amino acid will form only one dipeptide.

    The correct answer is: 1

     

  • Question 5/6
    1 / -0

    The two forms of D-glucopyranose obtained from the solution of D-glucose are better called

    Solutions

    The two isomeric forms (α−and β−) of D−glucopyranose differ in configuration only at C-1. Hence these are called anomers.

    The correct answer is: anomers

  • Question 6/6
    1 / -0

    The possible number of diastereomers for D-glucose is

    Solutions

    Total number of stereoisomers for D-glucose, having four chiral atoms, is 24=16; of which two (D-glucose and L-glucose) are enantiomers so number of diastereomers of D-glucose will be 14.

    The correct answer is: 14

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